0=(4(x^2-12))/(9(x^2-4)^(4/3))

Simple and best practice solution for 0=(4(x^2-12))/(9(x^2-4)^(4/3)) equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 0=(4(x^2-12))/(9(x^2-4)^(4/3)) equation: 


D( x )

9*(x^2-4)^(4/3) = 0

9*(x^2-4)^(4/3) = 0

9*(x^2-4)^(4/3) = 0

( 9 )

9 = 0

x belongs to the empty set

( x^2-4 )

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x in (-oo:-2) U (-2:2) U (2:+oo)

0 = (4*(x^2-12))/(9*(x^2-4)^(4/3)) // - (4*(x^2-12))/(9*(x^2-4)^(4/3))

0-((4*(x^2-12))/(9*(x^2-4)^(4/3))) = 0

(-4/9)*(x^2-4)^(-(4/3))*(x^2-12) = 0

-4/9*(x^2-4)^(4/3)*(x^2-12) = 0

( -4/9 )

-4/9 = 0

x belongs to the empty set

( x^2-12 )

1*x^2 = 12 // : 1

x^2 = 12

x^2 = 12 // ^ 1/2

abs(x) = 2*3^(1/2)

x = 2*3^(1/2) or x = -(2*3^(1/2))

( x^2-4 )

1*x^2 = 4 // : 1

x^2 = 4

x^2 = 4 // ^ 1/2

abs(x) = 2

x = 2 or x = -2

x in { 2} 

x in { -2} 

x in { 2*3^(1/2), -(2*3^(1/2)) }

See similar equations:

| a+6+a-2= | | x-(-37)=65 | | 6=3(4k-14) | | log(9)(2x+7)-log(9)(x-1)=log(9)(x-7) | | y=(-12)+5 | | 18=-4 | | X+(x+2)+(6x+10)=180 | | 6x+14+x=180 | | (-10)+n=5 | | v=1728in^3 | | (x+2)(6x+10)+x=180 | | X-90=4y | | 5m+24=2 | | -65-8=10 | | n=(-30)+(-23) | | 0.6x+3.12=x-0.08 | | x+2=3o | | 2x^2-4-240=0 | | X+9=-2x-6 | | 2(y+2)-2y=14 | | 5X+15Y=150 | | 0.6n=0.1n+2 | | 11/24-3/10 | | 28=5g-2 | | x+105=x+85 | | 4n+3+2n-7=2 | | -15n-6-14n-8=13 | | Ln(x-2)=ln(10x) | | x+(18)=-13 | | Ln(6)-ln(x-5)-ln(x)=0 | | Y-1=3(x+7) | | 2/5=14/× |

Equations solver categories